[omniORB] basic question about sequences

[Michael]

Hi Michel,

please check my last email:

> Anyway, you're right about initializing the out parameter, there
> should've been be a line
>
>seq_out = new seq_type;

> in my example

so

void Foo_impl::bar(const seq_type& seq_in, seq_type_out seq_out)
{
  seq_out = new seq_type;
  seq_out->length(seq_in.length());
  for (unsigned int i=0; i<seq_in.length(); ++i)
  {
 	 seq_out[i] = seq_in[i]*2;
  }
}

should work ok



debutant wrote:
> Thank you Michael, thank you Clarke !
> 
> I tried first:
> 
> seq_type* Foo_impl::bar(const seq_type& seq_in)
> {
> 	std::auto_ptr<seq_type> ret(new seq_type);
> 	ret->length(seq_in.length());
> 	for (unsigned int i=0; i<seq_in.length(); ++i)
> 	{
> 		(*ret)[i] = seq_in[i]*3;
> 	}
> 	return ret.release();
> } 
> 
> and it works well.
> 
> then I tried:
> 
> void Foo_impl::bar(const seq_type& seq_in, seq_type_out seq_out)
> {
>   seq_out->length(seq_in.length());
>   for (unsigned int i=0; i<seq_in.length(); ++i)
>   {
> 	 seq_out[i] = seq_in[i]*2;
>   }
> }
> 
> Line (3) gives me a problem (segmentation fault) (and (6) too). 
> 
> I looked at the .hh file generated by the idl compilation and saw:
> 
> class seq_type_out {
>   ...
> inline seq_type* operator->() { return _data; }
>   ...
> }
> 
> I tried:
> 
> 			 (seq_out.operator->())->length(seq_in.length());
> 
> and got the same problem. 
>  
> It seems that there is something wrong with the class seq_type_out ...
> 
> Thanks a lot for your help. I am still full of hope !
> Sincerely,
> Michel
>